Posts Tagged ‘value’

Question by Kit: What is an instance where the absolute value of a number (n) does not equal N?
I don’t know exactly how to ask the question, so I’ll write it as best I can as an equation; I n I *DOES NOT* = N
*face palm* Thank you. I feel like such a moron…. I -5 I > -5 …..

Best answer:

Answer by sahsjing
When n < 0, |n| > n

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Question by little miss sunshine :( : how do you solve absolute value inequalities?
specifically,
| d | > 2
i dont get it
i thought you made an or statement, like this

| d | > 2 or | d | > – 2

and the answer would be like, the absolute value of d is between negative two and two, and then you graph it. Help!

Best answer:

Answer by ted s
No, |d| < 2 means -2 < d < 2 and | d-5| < 2 means d is at most 2 units from 5...| d | > 3 means either d > 3 or d < -3 while | d - 5 | > 3 means d is at least 3 units away from 5…either d> 8 or d < 2

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Question by : how to get the absolute value of a sum function?
I have a sum function and I want the results as positive or absolute value

Best answer:

Answer by Silent
Give us a clue what programming language or environment we’re talking about here.

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Question by jldubs12: solve the provided absolute value inequality and graph the solution set?
I can do the graph but I am have in trouble getting the soulution set i think one of them is x>-12
the absolute value is /x+9/ > -3
i just need the solution set
please help

thanks

Best answer:

Answer by Puggy
|x + 9| > -3

This is a special case, since the absolute value ALWAYS returns a result 0 or greater. That is,

|x + 9| >= 0 (always true)

Since 0 > -3 (always true), by transitive property we get

|x + 9| > -3

So the solution set is all real numbers.

***** ******** ********* *********** **********

If by chance you instead meant |x + 9| > 3, then you have to use the following criteria:

1) If you get a form like |z| > c (or |z| >= c), (note: c must be positive; special things happen if c = 0 or c is negative, like the above example) this will translate into an OR. |z| > c translates into
(z > c) OR (z < -c)
|z| >= c translates into
(z >= c) OR (z < = -c)

2) If you get a form like |z| < c (or |z| <= c), this translates into an AND.

|z| < c is the same as saying
z < c AND z > -c, or the compound inequality
-z < c < z

|z| <= c is the same as saying
z <= c AND z >= -c, or the compound inequality
-c < = z <= c

So for the case of |x + 9| > 3, we would get

(x + 9 > 3) OR (x + 9 < -3)
(x > -6) OR (x < -12)

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Question by Matt K: What is the absolute value of infinity?
What is the absolute value of infinity? would it be undefined, 0, or all positive real numbers? Or is it an imaginary number.

Would like help from a math major, college math student, or a high level high school student(preferably 11th-12th grade).

Best answer:

Answer by Rodge453
It’s just infinity. All absolute value tells you is the distance away from 0 something is on the number line (so negatives become positive and positives stay positive).

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Question by a||en: Help solve confusing absolute value equation using interval notation?
Solve the (absolute value) equation below and put answer in interval notation? There is absolute value on both sides…

|2x| ≤ |2x-3|

Help please! Thanks in advance~

Best answer:

Answer by jeredwm
Maybe the easiest thing to do is just to square both sides! Notice that this cannot reverse the inequality since already both sides are non-negative.

This gives you the quadratic
4x² ≤ 4x² – 12x + 9
12x ≤ 9
x ≤ 3/4.

§

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Question by E: Algebra and absolute value function help?
Describe how the variables a, h, and k from the vertex form of an absolute value function , affect the transformation for the parent function y=|x|. Be sure to use math language, include graphs, t-tables, and algebraic examples.

Can someone please help me with this? I have to write a whole report answering this! It’s due tomorrow (Monday, January 27).
Oops sorry I mean Monday January 28. Today’s the 27th.

Best answer:

Answer by p lawes
You did not include a, h, or k in your problem, but h and k are usually with x and y respectively, and I am guessing the a is in front of the absolute value, or the f(x) symbol. Something like:

y = a|x- h| +k Right?

Maybe f(x) = a|x- h| +k

Ok,
The “h” shifts, or tranlates horizontally, the function in the OPPOSITE x direction. So |x + 2| would shift the graph 2 places to the LEFT, or the negative direction. Likewise, |x – 4| would shift it 4 place to the RIGHT, or the positive direction.

The “k” shift it up or down, but this time in the same direction.
+3 shift up, and -3 shifts down.

The “a” is a scalar and it is multiplied times the absolute value. Notice it is outside the function so we are scaling the “y” value. We call what the “a” does “scaling”. It does exactly what it says it does. 2|x| multiplies the y by 2.

Examples: y = |x + 3| shifts the x 3 places in the negative direction: to the left.

y = |x| + 3 shifts the y 3 places in the positive direction: upwards

y = 4|x| scales the y by 4. It expands it upwards 4 units.

What about combinations?

y = 3|x-1| – 4.

We know the 4 shifts it down 4, the -1 shifts it 1 to the RIGHT, and the 3 stretches the y number by 3.

But do I stretch first or shift down 4 first? For the y value, follow the order of operations. PEMDAS. Multiply the 3 then subtract the 4

*********************************************************************

as far as T-Tables, just make a function using numbers for h, k, and a. Then make a column for x and a column for y.
plug in the x and calculate the y!

Here’s a link that might help:

http://www.richland.edu/james/lecture/m116/functions/translations.html

**********************************************************************

Now for the Algebra; “Solve for the x, Substitute for the y”

Given a point on f(x), lets say (-5, 5), how can you find point on the new function, say y = -2|x + 3| – 4?

In the original function, your x number was -5 and your y number was 5.

In the equation, what’s in the absolute value is the x, and the absolute value itself is the y:

x+3 is the x, and |x+3| is the y

********* “Solve for x, Substitute for y” ********

“Solve for x” y = -2|x + 3| – 4

Your x numer is -5 so solve x+3 = -5. You get x = -8. You shifted 3 places to the left.

“Substitute for y” y = -2|x + 3| – 4

Your y number was 5, so -2(5) – 4 = -14

Your new point is (-8, -14). You can check by putting -8 in for x and see if you get -14 for y. (You do!)

For the point (0, 0) what would the new point be?

Solve for x: x + 3 = 0 (The x number), so x = -3
Substitute for y: -2(0) – 4 = -4, so y = -4
(-3, -4)
plug in the -3 for x and check that you get the -4 for y.

For the point (-1,1), what would the new point be?

Solve for x: x+3 = -1, x = -4
Substitute for y: -2(1) – 4 = -6, y = -6
(-4, -6)

It works for any function. In y = x^2 we have the point (2, 4)
Find the corresponding point be on y = 2(x-1)^2 + 3
The thing being squared is the x, and what I get after I square it is the y:

In the function y = 2(x-1)^2 + 3 the x is the (x-1), and the y is the (x – 1)^2

Solve for x, substitute for y>
x – 1 = 2, x = 3
2(4) + 3, y = 11

(3, 11) double check by putting the 3 in the new function for x, and make sure you get 11 out for y. (You do!)

what would the corresponding point be for (-3, 9)?

Scroll down to see the answer

(-2, 21) :-) check and see!
Good luck!

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Question by : If the price elasticity of demand for apples is 2.5 (in absolute value), then an increase in the price of app?
If the price elasticity of demand for apples is 2.5 (in absolute value), then an increase in the price of apple will……….

A. lower total revenue.
B.raise total revenue.
C.not affect total revenue.
D. either raise or lower total revenue, but it is impossible to determine which.

Best answer:

Answer by Anjaree
The answer is A. It is elastic. An increase in price will cause the demand to decline even more.

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Question aside Andrea Answers*: excuse atomic enumerate 49 contingent how you fix which enumerate has the greater conclusive value.?
The the conclusive values ar of -7 and 5. Thanks forwards of time! *Someone is edge to baffle those decade points!*

Best answer:

Answer aside ChuckB
The conclusive esteem is the esteem of the enumerate excluding any sign. Abs(-7) is 7, Abs(5) is 5. 7 is greater than 5. and then the conclusive esteem of -7 is greater than the conclusive esteem of 5.

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Question aside : How doh you get the decade and atomic number 39 intercepts of associate atomic number 49 nursing conclusive appraise affair algebraically (without looking astatine graph)?
And that was but associate atomic number 49 nursing exercise of associate atomic number 49 nursing conclusive appraise function, ace call for to acknowledge the chemical formula for how to get decade and atomic number 39 intercepts for something with the formatting y=a|x-h|+k
For example….
y = 2|x-3|-4

How doh you algebraically, and aside that ace bastardly without but graphing it and determination it, get its decade and atomic number 39 intercepts?

Thanks adenine lot

Best answer:

Answer aside deoxythymidine monophosphate mac
to get the atomic number 39 intercept, you chaw decade atomic number 49 atomic number 33 0
so:
y=2|(0)-3|-4
y=2(3)-4
y=6-4–> =2

to get the decade intercept, you chaw atomic number 39 atomic number 49 atomic number 33 0
0=2|x-3|-4
and figure out for x.

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